sat suite question viewer
The line segment shown in the xy-plane represents one of the legs of a right triangle. The area of this triangle is square units. What is the length, in units, of the other leg of this triangle?
Explanation
Choice B is correct. The length of a segment in the xy-plane can be found using the distance formula, , where and are the endpoints of the segment. The segment shown has endpoints at and . Substituting and for and , respectively, in the distance formula yields , or , which is equivalent to , or . Let represent the length, in units, of the other leg of this triangle. The area, , of a right triangle can be calculated using the formula , where and are the lengths of the legs of the triangle. It's given that the area of the triangle is square units. Substituting for , for , and for in the formula yields . Multiplying both sides of this equation by yields . Dividing both sides of this equation by yields . Multiplying the numerator and denominator on the left-hand side of this equation by yields , or , which is equivalent to , or . Therefore, the length, in units, of the other leg of this triangle is .
Choice A is incorrect and may result from conceptual or calculation errors.
Choice C is incorrect. is equivalent to , which is the length, in units, of the line segment shown in the xy-plane, not the length, in units, of the other leg of the triangle.
Choice D is incorrect and may result from conceptual or calculation errors.